Optimal. Leaf size=264 \[ \frac{3}{2} i a^2 \sin ^{-1}(a x)^2 \text{PolyLog}\left (2,-e^{i \sin ^{-1}(a x)}\right )-\frac{3}{2} i a^2 \sin ^{-1}(a x)^2 \text{PolyLog}\left (2,e^{i \sin ^{-1}(a x)}\right )-3 a^2 \sin ^{-1}(a x) \text{PolyLog}\left (3,-e^{i \sin ^{-1}(a x)}\right )+3 a^2 \sin ^{-1}(a x) \text{PolyLog}\left (3,e^{i \sin ^{-1}(a x)}\right )+3 i a^2 \text{PolyLog}\left (2,-e^{i \sin ^{-1}(a x)}\right )-3 i a^2 \text{PolyLog}\left (2,e^{i \sin ^{-1}(a x)}\right )-3 i a^2 \text{PolyLog}\left (4,-e^{i \sin ^{-1}(a x)}\right )+3 i a^2 \text{PolyLog}\left (4,e^{i \sin ^{-1}(a x)}\right )-\frac{\sqrt{1-a^2 x^2} \sin ^{-1}(a x)^3}{2 x^2}-a^2 \sin ^{-1}(a x)^3 \tanh ^{-1}\left (e^{i \sin ^{-1}(a x)}\right )-6 a^2 \sin ^{-1}(a x) \tanh ^{-1}\left (e^{i \sin ^{-1}(a x)}\right )-\frac{3 a \sin ^{-1}(a x)^2}{2 x} \]
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Rubi [A] time = 0.357254, antiderivative size = 264, normalized size of antiderivative = 1., number of steps used = 18, number of rules used = 10, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.417, Rules used = {4701, 4709, 4183, 2531, 6609, 2282, 6589, 4627, 2279, 2391} \[ \frac{3}{2} i a^2 \sin ^{-1}(a x)^2 \text{PolyLog}\left (2,-e^{i \sin ^{-1}(a x)}\right )-\frac{3}{2} i a^2 \sin ^{-1}(a x)^2 \text{PolyLog}\left (2,e^{i \sin ^{-1}(a x)}\right )-3 a^2 \sin ^{-1}(a x) \text{PolyLog}\left (3,-e^{i \sin ^{-1}(a x)}\right )+3 a^2 \sin ^{-1}(a x) \text{PolyLog}\left (3,e^{i \sin ^{-1}(a x)}\right )+3 i a^2 \text{PolyLog}\left (2,-e^{i \sin ^{-1}(a x)}\right )-3 i a^2 \text{PolyLog}\left (2,e^{i \sin ^{-1}(a x)}\right )-3 i a^2 \text{PolyLog}\left (4,-e^{i \sin ^{-1}(a x)}\right )+3 i a^2 \text{PolyLog}\left (4,e^{i \sin ^{-1}(a x)}\right )-\frac{\sqrt{1-a^2 x^2} \sin ^{-1}(a x)^3}{2 x^2}-a^2 \sin ^{-1}(a x)^3 \tanh ^{-1}\left (e^{i \sin ^{-1}(a x)}\right )-6 a^2 \sin ^{-1}(a x) \tanh ^{-1}\left (e^{i \sin ^{-1}(a x)}\right )-\frac{3 a \sin ^{-1}(a x)^2}{2 x} \]
Antiderivative was successfully verified.
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Rule 4701
Rule 4709
Rule 4183
Rule 2531
Rule 6609
Rule 2282
Rule 6589
Rule 4627
Rule 2279
Rule 2391
Rubi steps
\begin{align*} \int \frac{\sin ^{-1}(a x)^3}{x^3 \sqrt{1-a^2 x^2}} \, dx &=-\frac{\sqrt{1-a^2 x^2} \sin ^{-1}(a x)^3}{2 x^2}+\frac{1}{2} (3 a) \int \frac{\sin ^{-1}(a x)^2}{x^2} \, dx+\frac{1}{2} a^2 \int \frac{\sin ^{-1}(a x)^3}{x \sqrt{1-a^2 x^2}} \, dx\\ &=-\frac{3 a \sin ^{-1}(a x)^2}{2 x}-\frac{\sqrt{1-a^2 x^2} \sin ^{-1}(a x)^3}{2 x^2}+\frac{1}{2} a^2 \operatorname{Subst}\left (\int x^3 \csc (x) \, dx,x,\sin ^{-1}(a x)\right )+\left (3 a^2\right ) \int \frac{\sin ^{-1}(a x)}{x \sqrt{1-a^2 x^2}} \, dx\\ &=-\frac{3 a \sin ^{-1}(a x)^2}{2 x}-\frac{\sqrt{1-a^2 x^2} \sin ^{-1}(a x)^3}{2 x^2}-a^2 \sin ^{-1}(a x)^3 \tanh ^{-1}\left (e^{i \sin ^{-1}(a x)}\right )-\frac{1}{2} \left (3 a^2\right ) \operatorname{Subst}\left (\int x^2 \log \left (1-e^{i x}\right ) \, dx,x,\sin ^{-1}(a x)\right )+\frac{1}{2} \left (3 a^2\right ) \operatorname{Subst}\left (\int x^2 \log \left (1+e^{i x}\right ) \, dx,x,\sin ^{-1}(a x)\right )+\left (3 a^2\right ) \operatorname{Subst}\left (\int x \csc (x) \, dx,x,\sin ^{-1}(a x)\right )\\ &=-\frac{3 a \sin ^{-1}(a x)^2}{2 x}-\frac{\sqrt{1-a^2 x^2} \sin ^{-1}(a x)^3}{2 x^2}-6 a^2 \sin ^{-1}(a x) \tanh ^{-1}\left (e^{i \sin ^{-1}(a x)}\right )-a^2 \sin ^{-1}(a x)^3 \tanh ^{-1}\left (e^{i \sin ^{-1}(a x)}\right )+\frac{3}{2} i a^2 \sin ^{-1}(a x)^2 \text{Li}_2\left (-e^{i \sin ^{-1}(a x)}\right )-\frac{3}{2} i a^2 \sin ^{-1}(a x)^2 \text{Li}_2\left (e^{i \sin ^{-1}(a x)}\right )-\left (3 i a^2\right ) \operatorname{Subst}\left (\int x \text{Li}_2\left (-e^{i x}\right ) \, dx,x,\sin ^{-1}(a x)\right )+\left (3 i a^2\right ) \operatorname{Subst}\left (\int x \text{Li}_2\left (e^{i x}\right ) \, dx,x,\sin ^{-1}(a x)\right )-\left (3 a^2\right ) \operatorname{Subst}\left (\int \log \left (1-e^{i x}\right ) \, dx,x,\sin ^{-1}(a x)\right )+\left (3 a^2\right ) \operatorname{Subst}\left (\int \log \left (1+e^{i x}\right ) \, dx,x,\sin ^{-1}(a x)\right )\\ &=-\frac{3 a \sin ^{-1}(a x)^2}{2 x}-\frac{\sqrt{1-a^2 x^2} \sin ^{-1}(a x)^3}{2 x^2}-6 a^2 \sin ^{-1}(a x) \tanh ^{-1}\left (e^{i \sin ^{-1}(a x)}\right )-a^2 \sin ^{-1}(a x)^3 \tanh ^{-1}\left (e^{i \sin ^{-1}(a x)}\right )+\frac{3}{2} i a^2 \sin ^{-1}(a x)^2 \text{Li}_2\left (-e^{i \sin ^{-1}(a x)}\right )-\frac{3}{2} i a^2 \sin ^{-1}(a x)^2 \text{Li}_2\left (e^{i \sin ^{-1}(a x)}\right )-3 a^2 \sin ^{-1}(a x) \text{Li}_3\left (-e^{i \sin ^{-1}(a x)}\right )+3 a^2 \sin ^{-1}(a x) \text{Li}_3\left (e^{i \sin ^{-1}(a x)}\right )+\left (3 i a^2\right ) \operatorname{Subst}\left (\int \frac{\log (1-x)}{x} \, dx,x,e^{i \sin ^{-1}(a x)}\right )-\left (3 i a^2\right ) \operatorname{Subst}\left (\int \frac{\log (1+x)}{x} \, dx,x,e^{i \sin ^{-1}(a x)}\right )+\left (3 a^2\right ) \operatorname{Subst}\left (\int \text{Li}_3\left (-e^{i x}\right ) \, dx,x,\sin ^{-1}(a x)\right )-\left (3 a^2\right ) \operatorname{Subst}\left (\int \text{Li}_3\left (e^{i x}\right ) \, dx,x,\sin ^{-1}(a x)\right )\\ &=-\frac{3 a \sin ^{-1}(a x)^2}{2 x}-\frac{\sqrt{1-a^2 x^2} \sin ^{-1}(a x)^3}{2 x^2}-6 a^2 \sin ^{-1}(a x) \tanh ^{-1}\left (e^{i \sin ^{-1}(a x)}\right )-a^2 \sin ^{-1}(a x)^3 \tanh ^{-1}\left (e^{i \sin ^{-1}(a x)}\right )+3 i a^2 \text{Li}_2\left (-e^{i \sin ^{-1}(a x)}\right )+\frac{3}{2} i a^2 \sin ^{-1}(a x)^2 \text{Li}_2\left (-e^{i \sin ^{-1}(a x)}\right )-3 i a^2 \text{Li}_2\left (e^{i \sin ^{-1}(a x)}\right )-\frac{3}{2} i a^2 \sin ^{-1}(a x)^2 \text{Li}_2\left (e^{i \sin ^{-1}(a x)}\right )-3 a^2 \sin ^{-1}(a x) \text{Li}_3\left (-e^{i \sin ^{-1}(a x)}\right )+3 a^2 \sin ^{-1}(a x) \text{Li}_3\left (e^{i \sin ^{-1}(a x)}\right )-\left (3 i a^2\right ) \operatorname{Subst}\left (\int \frac{\text{Li}_3(-x)}{x} \, dx,x,e^{i \sin ^{-1}(a x)}\right )+\left (3 i a^2\right ) \operatorname{Subst}\left (\int \frac{\text{Li}_3(x)}{x} \, dx,x,e^{i \sin ^{-1}(a x)}\right )\\ &=-\frac{3 a \sin ^{-1}(a x)^2}{2 x}-\frac{\sqrt{1-a^2 x^2} \sin ^{-1}(a x)^3}{2 x^2}-6 a^2 \sin ^{-1}(a x) \tanh ^{-1}\left (e^{i \sin ^{-1}(a x)}\right )-a^2 \sin ^{-1}(a x)^3 \tanh ^{-1}\left (e^{i \sin ^{-1}(a x)}\right )+3 i a^2 \text{Li}_2\left (-e^{i \sin ^{-1}(a x)}\right )+\frac{3}{2} i a^2 \sin ^{-1}(a x)^2 \text{Li}_2\left (-e^{i \sin ^{-1}(a x)}\right )-3 i a^2 \text{Li}_2\left (e^{i \sin ^{-1}(a x)}\right )-\frac{3}{2} i a^2 \sin ^{-1}(a x)^2 \text{Li}_2\left (e^{i \sin ^{-1}(a x)}\right )-3 a^2 \sin ^{-1}(a x) \text{Li}_3\left (-e^{i \sin ^{-1}(a x)}\right )+3 a^2 \sin ^{-1}(a x) \text{Li}_3\left (e^{i \sin ^{-1}(a x)}\right )-3 i a^2 \text{Li}_4\left (-e^{i \sin ^{-1}(a x)}\right )+3 i a^2 \text{Li}_4\left (e^{i \sin ^{-1}(a x)}\right )\\ \end{align*}
Mathematica [A] time = 4.43164, size = 317, normalized size = 1.2 \[ \frac{1}{16} a^2 \left (24 i \sin ^{-1}(a x)^2 \text{PolyLog}\left (2,e^{-i \sin ^{-1}(a x)}\right )+48 \sin ^{-1}(a x) \text{PolyLog}\left (3,e^{-i \sin ^{-1}(a x)}\right )-48 \sin ^{-1}(a x) \text{PolyLog}\left (3,-e^{i \sin ^{-1}(a x)}\right )+24 i \left (\sin ^{-1}(a x)^2+2\right ) \text{PolyLog}\left (2,-e^{i \sin ^{-1}(a x)}\right )-48 i \text{PolyLog}\left (2,e^{i \sin ^{-1}(a x)}\right )-48 i \text{PolyLog}\left (4,e^{-i \sin ^{-1}(a x)}\right )-48 i \text{PolyLog}\left (4,-e^{i \sin ^{-1}(a x)}\right )+2 i \sin ^{-1}(a x)^4+8 \sin ^{-1}(a x)^3 \log \left (1-e^{-i \sin ^{-1}(a x)}\right )-8 \sin ^{-1}(a x)^3 \log \left (1+e^{i \sin ^{-1}(a x)}\right )+48 \sin ^{-1}(a x) \log \left (1-e^{i \sin ^{-1}(a x)}\right )-48 \sin ^{-1}(a x) \log \left (1+e^{i \sin ^{-1}(a x)}\right )-12 \sin ^{-1}(a x)^2 \tan \left (\frac{1}{2} \sin ^{-1}(a x)\right )-12 \sin ^{-1}(a x)^2 \cot \left (\frac{1}{2} \sin ^{-1}(a x)\right )-2 \sin ^{-1}(a x)^3 \csc ^2\left (\frac{1}{2} \sin ^{-1}(a x)\right )+2 \sin ^{-1}(a x)^3 \sec ^2\left (\frac{1}{2} \sin ^{-1}(a x)\right )-i \pi ^4\right ) \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.167, size = 428, normalized size = 1.6 \begin{align*} -{\frac{ \left ( \arcsin \left ( ax \right ) \right ) ^{2}}{ \left ( 2\,{a}^{2}{x}^{2}-2 \right ){x}^{2}}\sqrt{-{a}^{2}{x}^{2}+1} \left ({a}^{2}{x}^{2}\arcsin \left ( ax \right ) -3\,ax\sqrt{-{a}^{2}{x}^{2}+1}-\arcsin \left ( ax \right ) \right ) }-{\frac{ \left ( \arcsin \left ( ax \right ) \right ) ^{3}{a}^{2}}{2}\ln \left ( 1+iax+\sqrt{-{a}^{2}{x}^{2}+1} \right ) }+{\frac{ \left ( \arcsin \left ( ax \right ) \right ) ^{3}{a}^{2}}{2}\ln \left ( 1-iax-\sqrt{-{a}^{2}{x}^{2}+1} \right ) }-3\,\arcsin \left ( ax \right ) \ln \left ( 1+iax+\sqrt{-{a}^{2}{x}^{2}+1} \right ){a}^{2}-3\,{a}^{2}\arcsin \left ( ax \right ){\it polylog} \left ( 3,-iax-\sqrt{-{a}^{2}{x}^{2}+1} \right ) +3\,\arcsin \left ( ax \right ) \ln \left ( 1-iax-\sqrt{-{a}^{2}{x}^{2}+1} \right ){a}^{2}+3\,{a}^{2}\arcsin \left ( ax \right ){\it polylog} \left ( 3,iax+\sqrt{-{a}^{2}{x}^{2}+1} \right ) +{\frac{3\,i}{2}}{a}^{2} \left ( \arcsin \left ( ax \right ) \right ) ^{2}{\it polylog} \left ( 2,-iax-\sqrt{-{a}^{2}{x}^{2}+1} \right ) -{\frac{3\,i}{2}}{a}^{2} \left ( \arcsin \left ( ax \right ) \right ) ^{2}{\it polylog} \left ( 2,iax+\sqrt{-{a}^{2}{x}^{2}+1} \right ) +3\,i{a}^{2}{\it polylog} \left ( 2,-iax-\sqrt{-{a}^{2}{x}^{2}+1} \right ) -3\,i{a}^{2}{\it polylog} \left ( 4,-iax-\sqrt{-{a}^{2}{x}^{2}+1} \right ) -3\,i{a}^{2}{\it polylog} \left ( 2,iax+\sqrt{-{a}^{2}{x}^{2}+1} \right ) +3\,i{a}^{2}{\it polylog} \left ( 4,iax+\sqrt{-{a}^{2}{x}^{2}+1} \right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\arcsin \left (a x\right )^{3}}{\sqrt{-a^{2} x^{2} + 1} x^{3}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-\frac{\sqrt{-a^{2} x^{2} + 1} \arcsin \left (a x\right )^{3}}{a^{2} x^{5} - x^{3}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\operatorname{asin}^{3}{\left (a x \right )}}{x^{3} \sqrt{- \left (a x - 1\right ) \left (a x + 1\right )}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\arcsin \left (a x\right )^{3}}{\sqrt{-a^{2} x^{2} + 1} x^{3}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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